Work = 0 in a calorimeter/isolated system?  [ENDORSED]

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Deanna_Nguyen_3L
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Joined: Fri Jul 22, 2016 3:00 am

Work = 0 in a calorimeter/isolated system?

Postby Deanna_Nguyen_3L » Sun Jan 15, 2017 2:29 pm

During lecture it was said that if Vol (reactants) = Vol (products) then deltaH = deltaU. This is because deltaU = qp + W, but W is equal to 0 so deltaU=deltaH. Why is work (W) equal to 0?

Maria_Contreras_3A
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Re: Work = 0 in a calorimeter/isolated system?  [ENDORSED]

Postby Maria_Contreras_3A » Sun Jan 15, 2017 4:20 pm

I think work=0 because since the volume would be constant there would be no change in volume for the equation. w=-P(delta)V.

Keitty_Calderon_1C
Posts: 9
Joined: Wed Nov 18, 2015 3:00 am

Re: Work = 0 in a calorimeter/isolated system?

Postby Keitty_Calderon_1C » Sun Jan 15, 2017 5:58 pm

The system is isolated so no energy can be exchanged with the outside which means that work equals zero.

helen_bui_2G
Posts: 12
Joined: Wed Sep 21, 2016 2:57 pm

Re: Work = 0 in a calorimeter/isolated system?

Postby helen_bui_2G » Thu Jan 19, 2017 9:45 am

I went to discussion, and my TA said that work = 0 because like the other person said previously, the volume is constant. Since work depends on the ΔV, and ΔV=0, there is no work done, making w=0.


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