4 posts • Page 1 of 1
Since this is a bomb calorimeter, heat can't go in and out of the system (it's isolated). Therefore heat(q) of the entire system is 0. Therefore any heat lost by an exothermic reaction will warm up the calorimeter, or any heat absorbed by an endothermic reaction will come from the calorimeter and cool it down because there is nowhere else for this heat to go or come from. So the heat change of the reaction is equal and opposite to the heat change of the calorimeter, meaning their sum is 0.
Who is online
Users browsing this forum: Bing [Bot] and 3 guests