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HW 8.53

Posted: Wed Jan 18, 2017 9:25 pm
by Josue_Marin_3I
Why is it that q(reaction) + q(calorimeter)=0 ?

Re: HW 8.53

Posted: Wed Jan 18, 2017 11:03 pm
by Rachel_Smith_3D
Since this is a bomb calorimeter, heat can't go in and out of the system (it's isolated). Therefore heat(q) of the entire system is 0. Therefore any heat lost by an exothermic reaction will warm up the calorimeter, or any heat absorbed by an endothermic reaction will come from the calorimeter and cool it down because there is nowhere else for this heat to go or come from. So the heat change of the reaction is equal and opposite to the heat change of the calorimeter, meaning their sum is 0.

Re: HW 8.53

Posted: Sat Jan 21, 2017 8:29 pm
by Cobie_Allen_1H
So essentially no heat leaves or enters the calorimeter, it is just that the heat is absorbed or given off within the isolated system? Please correct me if I am wrong, I was a little confused by that as well.

Re: HW 8.53

Posted: Mon Jan 23, 2017 11:54 pm
by Myra_Zhan_2N
Another important thing to remember is that q will always equal 0 in an adiabatic process in a closed system. q cannot be negative or positive because no heat is added or removed.