Chp. 8 hwk

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NicoleRivas3J
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Joined: Wed Sep 21, 2016 2:58 pm

Chp. 8 hwk

Postby NicoleRivas3J » Sun Jan 22, 2017 5:21 pm

I'm confused on how to go about answering Chp. 8 question number 103..??

Spencer Peterman 3E
Posts: 18
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Re: Chp. 8 hwk

Postby Spencer Peterman 3E » Sun Jan 22, 2017 7:39 pm

The molar kinetic energy of a noble gas is equal to (3/2)RT (there's an explanation for this on pages 277-278 of the textbook), where R = 8.314 J/K/mol and T is the temperature in Kelvin. So for part (a) you would calculate (3/2)(8.314)(55.85+273).


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