Isothermal system

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Tiffany Cao 1D
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Joined: Fri Sep 29, 2017 6:03 am
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Isothermal system

Postby Tiffany Cao 1D » Wed Feb 14, 2018 2:26 pm

Why delta S of the surroundings 0 in an isothermal, free expansion process?

Curtis Tam 1J
Posts: 105
Joined: Thu Jul 13, 2017 2:00 am

Re: Isothermal system

Postby Curtis Tam 1J » Wed Feb 14, 2018 2:29 pm

Because the surroundings is basically a vacuum. The system is expanding but there is no heat transfer between the system and the surroundings so the surroundings basically remains unchanged.

Tatiana Hage 2E
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Re: Isothermal system

Postby Tatiana Hage 2E » Wed Feb 14, 2018 2:42 pm

Work = 0 in free expansion because there is no external pressure applied, so P=0 and therefore w=0. Since ΔU = 0, that means that q=0 as well, so no heat is transferred into the surroundings.

mayapartha_1D
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Joined: Fri Sep 29, 2017 6:07 am

Re: Isothermal system

Postby mayapartha_1D » Mon Feb 19, 2018 3:08 pm

Hi Tiffany!

Because q=0 as there is no transfer of heat or change in temp (isothermal) there will be no change in entropy of the molecules.

704887365
Posts: 49
Joined: Sat Jul 22, 2017 2:00 am

Re: Isothermal system

Postby 704887365 » Tue Mar 06, 2018 8:11 am

Work = 0 in free expansion because there is no external pressure applied, so P=0 and therefore w=0. Since ΔU = 0, that means that q=0 as well, so no heat is transferred into the surroundings.

Rishi Khettry 1L
Posts: 29
Joined: Fri Sep 29, 2017 6:05 am

Re: Isothermal system

Postby Rishi Khettry 1L » Fri Mar 16, 2018 6:16 pm

The term free expansion implies work is = 0 and in that case q would also be zero as the deltaU value needs to remain 0


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