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A reversible process is one that is infinitely slow because it is at equilibrium (any slight change to the reaction can cause a shift, which is why it's called reversible). If the system is doing work on the surroundings, more work is done if the process goes by slowly (because then, less heat is lost to the surroundings). Therefore, a reversible process (infinitely slow) does the maximum work.
The higher the temperature, the higher the gas pressure will be, so the expansion takes place against a stronger opposing force and therefore must do more work. So therefore, the reversible reaction will be doing more work compared to the others.
MackenziePerillo-1L wrote:Will the reverse reaction always be doing more work than the forward reaction?
I think that what they are discussing is a reversible reaction (where the system isn't at equilibrium and the change will be definite) as opposed to an irreversible reaction (where the system is at equilibrium and changes occur in infinitely small steps) instead of a forward and reverse reaction. The reversible reaction will always do more work than the irreversible reaction.
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