Textbook question 4B.9

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Paige Lee 1A
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Joined: Sat Sep 07, 2019 12:16 am

Textbook question 4B.9

Postby Paige Lee 1A » Thu Feb 06, 2020 12:25 am

For parts A and D, why must w=0 in an adiabatic process?

Alicia Lin 2F
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Re: Textbook question 4B.9

Postby Alicia Lin 2F » Thu Feb 06, 2020 12:31 pm

in an adiabatic process, energy can only be transferred as work, not heat.

a) Because deltaU=q+w, and we know q=0 (because no heat is transferred), deltaU can only be 0 if w is also 0.

d) Using similar reasoning, deltaU can only equal q if the other component of the equation (w) is set to 0, giving deltaU=q+0, which simplifies to deltaU=q

Ying Yan 1F
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Re: Textbook question 4B.9

Postby Ying Yan 1F » Sun Feb 09, 2020 4:16 pm

Since no heat is exchanged with its surrounding, q=0. Thus since -q=w, w will also be 0.

CalvinTNguyen2D
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Re: Textbook question 4B.9

Postby CalvinTNguyen2D » Sun Feb 09, 2020 5:02 pm

In adiabatic processes, heat is not transferred in or out of a system. Therefore, q is equal to 0, allowing us to determine w (work) from inference and deductions.

Celine 1F
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Re: Textbook question 4B.9

Postby Celine 1F » Sun Feb 09, 2020 6:38 pm

In adiabatic processes, there is no heat transfer, so q is = to 0.


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