4A.5

Moderators: Chem_Mod, Chem_Admin

Yuzhe Yuan
Posts: 104
Joined: Fri Sep 24, 2021 6:38 am
Been upvoted: 1 time

4A.5

Postby Yuzhe Yuan » Sun Jan 23, 2022 3:38 pm

Hi,

Can someone explain this question for me?
Attachments
屏幕截图 2022-01-23 152416.png

Erika Li 1E
Posts: 105
Joined: Fri Sep 24, 2021 5:37 am
Been upvoted: 2 times

Re: 4A.5

Postby Erika Li 1E » Mon Jan 24, 2022 5:51 pm

For part (a), since the gas is expanding under constant pressure, you would use the equation w = -P * delta V to find the work done. The pressure is 1 atm and the change in volume is 1.20 L (both are given in the problem). Part (b) is an example of isothermal, reversible expansion so you would use this equation w = -nRTln(V2/V1) to find the work done. The number of moles of Ne, the temperature, and initial and final volume are given in the problem so you can plug in those values to find the work done. Hope this helps!

Natalie Keung 1D
Posts: 138
Joined: Fri Sep 24, 2021 5:47 am
Been upvoted: 1 time

Re: 4A.5

Postby Natalie Keung 1D » Mon Jan 24, 2022 5:56 pm

I did the exact same as Erika said. Another note is just that typically when there is an irreversible reaction and a reversible reaction, it is likely that the reversible one will do more work and you tend to use those two equations respectively to determine the work of both irreversible and reversible reactions.

MaiVyDang2I
Posts: 104
Joined: Fri Sep 24, 2021 6:52 am

Re: 4A.5

Postby MaiVyDang2I » Mon Jan 24, 2022 6:19 pm

From the textbook, it says that under constant pressure (irreversible), w=-P delta V. And when it's reversible, w= -nRT ln(V2/V1).


Return to “Thermodynamic Systems (Open, Closed, Isolated)”

Who is online

Users browsing this forum: No registered users and 2 guests