## Expansion work

isochoric/isometric: $\Delta V = 0$
isothermal: $\Delta T = 0$
isobaric: $\Delta P = 0$

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JukaKim_1D
Posts: 24
Joined: Fri Sep 25, 2015 3:00 am

### Expansion work

What does it mean when problems state no expansion work? does that mean that the volume doesn't change? how else would it do work if the volume does not change?

Johnchou1A
Posts: 37
Joined: Fri Sep 25, 2015 3:00 am

### Re: Expansion work

When it states "no expansion work," deltaV is 0. When deltaV is 0, it means that there is no work done, and that the only change in internal energy will be due to heat. Thus, deltaU = q

Darlene Fung 1J
Posts: 20
Joined: Fri Sep 25, 2015 3:00 am

### Re: Expansion work

Yes it means that the volume doesn't change. Instead, work is done by heat.

amyjunus1A
Posts: 26
Joined: Fri Sep 25, 2015 3:00 am

### Re: Expansion work

To make it even easier to understand, keep in mind that work can be converted to heat, and (although not all may be transferred) thus heat can be converted to work! Thus no change in volume (even though its the most common way to make work) is necessary for work. Hopefully this helps a little.

Chem_Mod
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### Re: Expansion work

Besides mechanical work (by expansion), there are also chemical and electrical work. Heat is a kind of energy, it is not work. It can be converted to work by expanding the system. In this case it simply means there is no mechanical work which means no volume change.

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