K constant

[Noah Chriqui 2H]

If K = 1, why does delta G = 0?

[Everest Cheng 2J]

If K=1, then the reaction is at equilibrium. At equilibrium, ΔG of the reaction is 0 because there is no change in free energy.

[Jeannie Kennedy 3F]

K constant is equal to 1 because when K is equal to 1 that indicates the system is at equilibrium. Whereas, delta G is equal to 0 because Gibbs free energy is at equilibrium and there is no net change in the system.

[morgan 1I]

If K=1, it means that the reaction has reached equilibrium (the rate of the forward and reverse reactions is equal). For a reaction at constant temperature and pressure, if change in G is 0, then the system is at equilibrium. For example, A + B <—> C. If you write the expression for the equilibrium constant, you get: Keq=([C])/([A][B]). If the system above is in equilibrium, the concentration of C will be equal to the concentration of A times the concentration of B. Therefore, the fraction will equal 1. If that fraction equals 1, K=1.

[Daniel Chang 1K]

K = 1 means the chemical reaction is at equilibrium; as a result, delta G would be 0 because there is 0 net movement in free energy.

[Katie L 2I]

also, if we plug the value of K = 1 into the Gibbs free energy equation with ∆Gº = -RTlnK, ln of 1 = 0, so ∆Gº would equal 0, fitting with the conceptual descriptions of the reaction being at dynamic equilibrium that other people have been talking about.