"Favorable" chemical reaction


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"Favorable" chemical reaction

Postby Benjamin_Oh_3O » Mon Jan 23, 2017 3:56 pm

Can anyone please explain the favorable chemical reaction and what will happen?
In page 27 of the course reader, there was an example of chemical reaction:

C6H12O6 + 6O2 -> 6CO2 + 6H2O

In the podcast, Dr. Lavelle says that this reaction will be a favorable reaction. But I don't know how he could figure out why that's the case.

Please anyone help me to understand this concept!


Danny Nguyen 2H
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Joined: Fri Jul 22, 2016 3:00 am

Re: "Favorable" chemical reaction

Postby Danny Nguyen 2H » Mon Jan 23, 2017 5:01 pm

The reason Professor Lavelle called it "favorable" because it's spontaneous; meaning the reaction is moving in a way that is "favorable" or in the natural direction. Like the example he gives with a rock in a valley. If the rock is on the edge, its rolling down the hill naturally. But if it's in the trench of the valley, it's not going to, by itself, roll back up the hill because that's not likely or favorable at all. Also to answer your question, the reaction in the book is favorable, because it's going from low entropy to a higher entropy and as always higher entropy is favored.

Janice Kim 3I
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Joined: Wed Sep 21, 2016 2:56 pm

Re: "Favorable" chemical reaction

Postby Janice Kim 3I » Wed Jan 25, 2017 12:42 pm

This reaction is exothermic, meaning that the products are at a lower energy state than the reactants are. Usually, molecules will want to achieve the lowest energy state possible, and in this reaction, exactly that is happening. This reaction was favorable because it happened by itself, making it a spontaneous reaction.

Yuchien Ma 2L
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Joined: Wed Sep 21, 2016 2:58 pm

Re: "Favorable" chemical reaction

Postby Yuchien Ma 2L » Sun Jan 29, 2017 1:30 pm

When delta G is negative, the reaction is favorable (spontaneous).
When delta G is positive, the reaction is unfavorable (non-spontaneous).
When delta G is equal to zero, the system is at equilibrium.

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