## "Favorable" chemical reaction

isochoric/isometric: $\Delta V = 0$
isothermal: $\Delta T = 0$
isobaric: $\Delta P = 0$

Benjamin_Oh_3O
Posts: 9
Joined: Wed Sep 21, 2016 2:55 pm

### "Favorable" chemical reaction

Can anyone please explain the favorable chemical reaction and what will happen?
In page 27 of the course reader, there was an example of chemical reaction:

C6H12O6 + 6O2 -> 6CO2 + 6H2O

In the podcast, Dr. Lavelle says that this reaction will be a favorable reaction. But I don't know how he could figure out why that's the case.

Please anyone help me to understand this concept!

Thanks,

Danny Nguyen 2H
Posts: 17
Joined: Fri Jul 22, 2016 3:00 am

### Re: "Favorable" chemical reaction

The reason Professor Lavelle called it "favorable" because it's spontaneous; meaning the reaction is moving in a way that is "favorable" or in the natural direction. Like the example he gives with a rock in a valley. If the rock is on the edge, its rolling down the hill naturally. But if it's in the trench of the valley, it's not going to, by itself, roll back up the hill because that's not likely or favorable at all. Also to answer your question, the reaction in the book is favorable, because it's going from low entropy to a higher entropy and as always higher entropy is favored.

Janice Kim 3I
Posts: 33
Joined: Wed Sep 21, 2016 2:56 pm

### Re: "Favorable" chemical reaction

This reaction is exothermic, meaning that the products are at a lower energy state than the reactants are. Usually, molecules will want to achieve the lowest energy state possible, and in this reaction, exactly that is happening. This reaction was favorable because it happened by itself, making it a spontaneous reaction.

Yuchien Ma 2L
Posts: 46
Joined: Wed Sep 21, 2016 2:58 pm

### Re: "Favorable" chemical reaction

When delta G is negative, the reaction is favorable (spontaneous).
When delta G is positive, the reaction is unfavorable (non-spontaneous).
When delta G is equal to zero, the system is at equilibrium.