## Conversion Factor 101.325 J/L*atm

isochoric/isometric: $\Delta V = 0$
isothermal: $\Delta T = 0$
isobaric: $\Delta P = 0$

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### Conversion Factor 101.325 J/L*atm

Hello Professor Lavelle!
How did the book get 101.325 $\frac{J}{L\: atm}$?
Thank you! Katherine

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### Re: Conversion Factor 101.325 J/L*atm

101.325 is the conversion of kPa to atm (101.325 kPa = 1 atm). The units of pascals and liters are required for the work equation to have the resulting answer be in units of joules.
W (J) = -P (Pa) x [$V_{2}-V_{1}$] (L)

Further, 1 J = 1 Pa*m3. To get the relationship between Joules and L*atm:
1 L*atm= $\frac{101325 Pa}{1 atm}$ x $\frac{10^{-3} m^3}{1 L}$ = 101.325 Pa*m3 = 101.325 J