Work

isochoric/isometric:
isothermal:
isobaric:

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Tiffany Cao 1D
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Joined: Fri Sep 29, 2017 7:03 am
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Work

Postby Tiffany Cao 1D » Wed Feb 14, 2018 10:14 am

Am I right by saying that if volume does not change,if a gas expands in a vacuum, and if a gas undergoes free expansion, work is 0?

Michelle Chernyak 1J
Posts: 33
Joined: Fri Sep 29, 2017 7:06 am

Re: Work

Postby Michelle Chernyak 1J » Wed Feb 14, 2018 10:17 am

Yes you are correct. There s no work being done as a gas expands in a volume because there is no opposing force.

RuchaDeshpande1L
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Re: Work

Postby RuchaDeshpande1L » Wed Feb 14, 2018 10:26 am

Work done by expansion can be calculated by using w = -P * delta V. If delta V is zero, then there is no expansion occurring, and thus the overall work done is also zero. Note that under constant volume conditions, the change in internal energy of the system is given by qv and that the change in internal energy results from only the heat released by the reaction.

RohanGupta1G
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Joined: Sat Jul 22, 2017 3:00 am

Re: Work

Postby RohanGupta1G » Wed Feb 14, 2018 10:35 am

That is correct because the work done is a vacuum is 0 because there is no pressure or opposing force.

Patricia Macalalag 2E
Posts: 53
Joined: Sat Jul 22, 2017 3:00 am

Re: Work

Postby Patricia Macalalag 2E » Fri Feb 16, 2018 8:39 pm

Yes, w=0.

Paula Dowdell 1F
Posts: 72
Joined: Tue Nov 15, 2016 3:00 am

Re: Work

Postby Paula Dowdell 1F » Sat Feb 17, 2018 12:14 pm

It's good to note that work is zero if applied force is zero (W=0 if F=0).


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