Internal Energy

isochoric/isometric:
isothermal:
isobaric:

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Hanniel U 2B
Posts: 76
Joined: Fri Sep 28, 2018 12:16 am

Internal Energy

Postby Hanniel U 2B » Sat Feb 02, 2019 8:07 pm

Can someone please help me with 4B.5 7th edition?

keyaluo4C
Posts: 54
Joined: Fri Sep 28, 2018 12:17 am

Re: Internal Energy

Postby keyaluo4C » Sat Feb 02, 2019 10:17 pm

1. Start with w:


2. Calculate


3. Convert the given from Torr to atm


4. Plug into equation for w


5. Convert to kJ

6. Calculate change in internal energy using

Hanniel U 2B
Posts: 76
Joined: Fri Sep 28, 2018 12:16 am

Re: Internal Energy

Postby Hanniel U 2B » Sat Feb 02, 2019 11:03 pm

keyaluo4C wrote:1. Start with w:


2. Calculate


3. Convert the given from Torr to atm


4. Plug into equation for w


5. Convert to kJ

6. Calculate change in internal energy using

Thank You!!!

Matthew ILG 1L
Posts: 112
Joined: Sat Aug 17, 2019 12:15 am

Re: Internal Energy

Postby Matthew ILG 1L » Sun Feb 09, 2020 10:42 pm

I was just on this problem and luckily found this post. Are we supposed to know that 1atm is equivalent to 760 torr or is that somewhere on the equation sheet? Also how do we convert from L*atm to kJ?

Amy Kumar 1I
Posts: 114
Joined: Thu Jul 11, 2019 12:15 am

Re: Internal Energy

Postby Amy Kumar 1I » Mon Feb 10, 2020 3:12 am

Matthew ILG 1L wrote:I was just on this problem and luckily found this post. Are we supposed to know that 1atm is equivalent to 760 torr or is that somewhere on the equation sheet? Also how do we convert from L*atm to kJ?


Both conversions are given on the constants and equations sheet.
1 L.atm = 101.325 J
1 atm = 760 torr


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