## Internal Energy

isochoric/isometric: $\Delta V = 0$
isothermal: $\Delta T = 0$
isobaric: $\Delta P = 0$

Hanniel U 2B
Posts: 76
Joined: Fri Sep 28, 2018 12:16 am

### Internal Energy

keyaluo4C
Posts: 54
Joined: Fri Sep 28, 2018 12:17 am

### Re: Internal Energy

$w=-P_{ex}\Delta V$

2. Calculate $\Delta V$
$\Delta V=1.846L-0.345L=1.501L$

3. Convert the given $P_{ex}$ from Torr to atm
$P_{ex}=750 \textup{ torr } \times \frac{1 \textup{ atm}}{760 \textup{ Torr}}=.99\textup{ atm}$

4. Plug into equation for w
$w=-.99 \times 1.5 =-1.49 \textup{L}\cdot \textup{atm}$

5. Convert to kJ

6. Calculate change in internal energy using $\Delta U=q + w$
$\Delta U = 5.35 \textup{\textup{ kJ}}$

Hanniel U 2B
Posts: 76
Joined: Fri Sep 28, 2018 12:16 am

### Re: Internal Energy

$w=-P_{ex}\Delta V$

2. Calculate $\Delta V$
$\Delta V=1.846L-0.345L=1.501L$

3. Convert the given $P_{ex}$ from Torr to atm
$P_{ex}=750 \textup{ torr } \times \frac{1 \textup{ atm}}{760 \textup{ Torr}}=.99\textup{ atm}$

4. Plug into equation for w
$w=-.99 \times 1.5 =-1.49 \textup{L}\cdot \textup{atm}$

5. Convert to kJ

6. Calculate change in internal energy using $\Delta U=q + w$
$\Delta U = 5.35 \textup{\textup{ kJ}}$

Thank You!!!