## 9.35 Sixth Edition

isochoric/isometric: $\Delta V = 0$
isothermal: $\Delta T = 0$
isobaric: $\Delta P = 0$

Alexa Tabakian 1A
Posts: 38
Joined: Fri Sep 28, 2018 12:20 am

### 9.35 Sixth Edition

Container A is filled with 1.0 mol of the atoms of an ideal monatomic gas. Container B has 1.0 mol of atoms bound together as diatomic molecules that are not vibrationally active. Container C has 1.0 mol of atoms bound together as diatomic molecules that are vibrationally active.

How do you determine which has the least entropy and which has the most?

Miriam Sheetz 2B
Posts: 64
Joined: Fri Sep 28, 2018 12:25 am

### Re: 9.35 Sixth Edition

Container a has the least because it contains monatomic atoms and container c has the most entropy because it contains diatomic molecules that are active. Entropy is essentially the disorder of the system so if you consider all 3 containers, container a will has the least disorder because it only has monatomic atoms. Container b will have the second most entropy because it has diatomic atoms, but they are not moving. The container c has the most entropy because it has diatomic atoms that are moving so it is the most disordered.

Alexa Tabakian 1A
Posts: 38
Joined: Fri Sep 28, 2018 12:20 am

### Re: 9.35 Sixth Edition

The book says container A has the most entropy, then C, then B.