## C in nCv ln (T2/T1)

isochoric/isometric: $\Delta V = 0$
isothermal: $\Delta T = 0$
isobaric: $\Delta P = 0$

Jason Wu 1E
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### C in nCv ln (T2/T1)

What is the C represent? I thought it was a heat capacity but why is it capitalized? is it a constant? or does it depend on the compound at hand? Also when is it applicable for us to use the equation?

KaleenaJezycki_1I
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### Re: C in nCv ln (T2/T1)

C in Cv is heat capacity and will most likely be the heat capacity of a monoatomic gas : Cv= 3/2R

nicole-2B
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### Re: C in nCv ln (T2/T1)

If it is under constant pressure C equals Cp=5/2*R for a monatomic gas

Leslie Almaraz 4G
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### Re: C in nCv ln (T2/T1)

this is the heat capacity of the system at constant volume

Leslie Almaraz 4G
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### Re: C in nCv ln (T2/T1)

there is also a different way to find Cv and Cp for mono and diatomic molecules.

Sanjana Munagala_1j
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### Re: C in nCv ln (T2/T1)

You need to also be cautious when you have a system that has an entropy change due to both a temperature change and a volume change. When you calculate the entropy change for just the temperature change you have to make the assumption that the volume is constant.

Hope that helps!

Eva Zhao 4I
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### Re: C in nCv ln (T2/T1)

To add on, the relationship between Cv and Cp is Cp = Cv + 1. The values for Cv are shown below (know that we look at the ideal gas values):

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### Re: C in nCv ln (T2/T1)

Eva Zhao 4I wrote:To add on, the relationship between Cv and Cp is Cp = Cv + 1. The values for Cv are shown below (know that we look at the ideal gas values):

It's not one it is actually R, the gas constant. Cp=Cv + R

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### Re: C in nCv ln (T2/T1)

Cv=3R/2
Cp=5/2R

5/2R=3R/2+R
5R-3R/2 --> 2R/2=R