constant volume/pressure


and

Moderators: Chem_Mod, Chem_Admin

oliviabruin24
Posts: 30
Joined: Mon Jan 09, 2023 1:32 am

constant volume/pressure

Postby oliviabruin24 » Sun Mar 17, 2024 2:13 pm

What does it mean when a problem says something occurs under contant pressure or constant volume? I know what these mean in a very literal sense, but how can I manipulate an equation if it has a variable in it that I can’t work with? Would I just plug in 0 or 1 for those? Could I omit them completely?

Chisomaga Azu
Posts: 83
Joined: Fri Sep 29, 2023 12:27 pm

Re: constant volume/pressure

Postby Chisomaga Azu » Sun Mar 17, 2024 2:21 pm

I think it varies based on the question. Sometimes when a question states that a problem occurs under constant volume, it usually is trying to indicate 0 work being done. If it states that the problem occurs under constant pressure, it might be trying to indicate to use the work equation w=p∆v. So it really just depends on the question.

006248274
Posts: 90
Joined: Fri Sep 29, 2023 10:32 am

Re: constant volume/pressure

Postby 006248274 » Sun Mar 17, 2024 2:24 pm

So because its a constant volume, q=change in internal energy because when there is no change in volume, no work is being done(-p delta V=0 bc delta V=0), so the equation delta U(internal energy)=q+w just becomes delta u=q. Then, because the definition of enthalpy, H=q+pv. Since v is 0, H= q at constant volume, and because delta u=q, then delta u also=H at constant volume


Return to “Calculating Work of Expansion”

Who is online

Users browsing this forum: No registered users and 4 guests