## Final 2011 Question 1B Combustion of Methane

$w=-P\Delta V$
and
$w=-\int_{V_{1}}^{V_{2}}PdV=-nRTln\frac{V_{2}}{V_{1}}$

Alex Nguyen 3I
Posts: 100
Joined: Fri Sep 25, 2015 3:00 am

### Final 2011 Question 1B Combustion of Methane

Suppose 1.00 mol of methane is combusted irreversibly at constant room temperature (25 degrees C). Calculate the work associated with this process.

In the solution, it indicates the process as:
CH4(g) + 2O2(g) --> 2H2O(l) + CO2(g)
and that delta n(gas) = -2.00

Isn't H2O water vapor (gas) not liquid? If not, can someone explain why it's a liquid?

Chem_Mod
Posts: 19622
Joined: Thu Aug 04, 2011 1:53 pm
Has upvoted: 889 times

### Re: Final 2011 Question 1B Combustion of Methane

It's because you're at room temperature.