Work with changeP and constant V

Emilie Hoffman 1E · Postby **Emilie Hoffman 1E** » Sat Mar 17, 2018 9:14 pm

Why is there no work done when a systems pressure changes but its volume does not?

Riya Pathare 2E · Postby **Riya Pathare 2E** » Sat Mar 17, 2018 9:15 pm

work is equal to -P*deltaV so when there is no volume change delta V will be 0 making work also equal to 0

SantanaRodriguezDis1G · Postby **SantanaRodriguezDis1G** » Sat Mar 17, 2018 9:17 pm

if delta v is equal to zero then work is equal to zero by the equation w=-pdeltav

SPandya1F · Postby **SPandya1F** » Sat Mar 17, 2018 9:18 pm

A gas enclosed by a piston in a cylinder can do work on the piston, the work being the pressure multiplied by the change in volume. If the volume doesn't change, no work is done. If there is no change in volume ( $\Delta$ V=0), work will equal 0.

Nora Sharp 1C · Postby **Nora Sharp 1C** » Sat Mar 17, 2018 9:19 pm

expansion work in a irreversible change = -P*deltaV, and when there is no change in V, deltaV = 0 so work = 0. This only holds true if we only consider expansion work.

expansion work in a reversible change = -nRT*(ln (Vfinal/Vinitial))
if vfinal = vinitial, then any expansion work also is zero.

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Work with changeP and constant V

Work with changeP and constant V

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