Work


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Kate_Santoso_4F
Posts: 72
Joined: Fri Sep 28, 2018 12:29 am

Work

Postby Kate_Santoso_4F » Wed Feb 06, 2019 9:32 am

If a problem indicates constant volume in one way or another, do we always assume w=0?

Seohyun Park 1L
Posts: 73
Joined: Fri Sep 28, 2018 12:29 am

Re: Work

Postby Seohyun Park 1L » Wed Feb 06, 2019 9:46 am

I'm assuming you do assume w=0 because the only work we consider in reactions is usually pressure-volume expansion and in constant volume, delta v= 0.

Sarah Fatkin 4I
Posts: 71
Joined: Fri Sep 28, 2018 12:27 am

Re: Work

Postby Sarah Fatkin 4I » Wed Feb 06, 2019 10:20 am

Yep! For example, if a system has constant pressure, we know that delta(V) = 0, so the work is zero.

Max Hayama 4K
Posts: 63
Joined: Fri Sep 28, 2018 12:16 am

Re: Work

Postby Max Hayama 4K » Wed Feb 06, 2019 10:35 am

Because the system is not doing any work against the surroundings to change the volume (or vise versa), it is safe to assume that under constant volume that no work is being done by or on the system.

Danny Elias Dis 1E
Posts: 60
Joined: Fri Sep 28, 2018 12:19 am

Re: Work

Postby Danny Elias Dis 1E » Fri Feb 08, 2019 10:05 am

Is this situation also the case where deltaU = q?

Krista Mercado 1B
Posts: 60
Joined: Fri Sep 28, 2018 12:26 am

Re: Work

Postby Krista Mercado 1B » Sat Feb 09, 2019 8:55 pm

Danny Elias Dis 1E wrote:Is this situation also the case where deltaU = q?

Yes, because ΔU = q+w, and if w = 0, then ΔU = q+0 = q.


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