## 6th edition self test 8.1A

$w=-P\Delta V$
and
$w=-\int_{V_{1}}^{V_{2}}PdV=-nRTln\frac{V_{2}}{V_{1}}$

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Karyn Nguyen 1K
Posts: 72
Joined: Fri Apr 06, 2018 11:04 am

### 6th edition self test 8.1A

Water expands when it freezes. How much work does 100. g of water do when it freezes at 0.0 C and pushes back the metal wall of a pipe that exerts an opposing pressure of 1070 atm? The densities of water and ice at 0.0C are 1.00 gcm3 and 0.92 gcm3, respectively.

I'm a little confused on how to solve this question, can someone please explain the steps to me?

ThomasLai1D
Posts: 61
Joined: Fri Sep 28, 2018 12:17 am

### Re: 6th edition self test 8.1A

Since w=-PdeltaV, and pressure is given, you need to find delta V. Given the densities of water, we can calculate the volume of water by multiplying 100g x 1 cm3/1g and the volume of ice by multiplying 100g x 1 cm3/0.92g. From there, you should have your change in volume (volume ice - volume water) and you can calculate work.

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