Reversible Expansion

$w=-P\Delta V$
and
$w=-\int_{V_{1}}^{V_{2}}PdV=-nRTln\frac{V_{2}}{V_{1}}$

Bianca Barcelo 4I
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Reversible Expansion

How/why does reversible expansion do the most work?

Celine Cheng 1H
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Re: Reversible Expansion

When examining the Pex vs V graph for reversible and irreversible, the area under the reversible curve is greater because Pex can change as well, so it is maximized. Any little change is responded to, whereas in irreversible reactions, super small changes don't really have an effect.

chris_tsai_4H
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Joined: Fri Sep 28, 2018 12:26 am

Re: Reversible Expansion

Reversible expansion does the most amount of work because the gas is pushing against the maximum possible external pressure and less of the energy is lost to heat.