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### Work without change in volume

Posted: Thu Feb 14, 2019 7:05 pm
How can you find work at a constant temperature when there is no change in the volume?

### Re: Work without change in volume

Posted: Thu Feb 14, 2019 8:58 pm
(If I understand you correctly)

In the case when the system is isothermal (constant temperature) and the system is under constant pressure, work can be defined as the external pressure times the change in volume. If there is no change in volume, no work is done.

### Re: Work without change in volume

Posted: Thu Feb 14, 2019 10:19 pm
as work is equal to -PdeltaV and there is no change in volume, the expression would equal zero and no work is done.

### Re: Work without change in volume

Posted: Fri Feb 15, 2019 8:19 pm
If there is no change in volume, no work will be done. If you are referring to an isothermal process with constant pressure, then I'm pretty sure work = -(external P)(Delta V).

### Re: Work without change in volume

Posted: Sun Feb 17, 2019 11:52 pm
if there is no change in volume then there cannot be any work done. remember, it doesnt matter how hard you push against the wall, if it doesnt move no work was done.

### Re: Work without change in volume

Posted: Wed Feb 20, 2019 6:09 pm
If there is no change in volume, that means that the system has not expanded or been compressed. If there is no expansion or compression, there is no work because the work that we are referring to is only expansion/compression work.

### Re: Work without change in volume

Posted: Thu Mar 14, 2019 12:50 pm
There is no work done as there is no change in volume.

### Re: Work without change in volume

Posted: Thu Mar 14, 2019 1:16 pm
No change in volume means no work is done.

### Re: Work without change in volume

Posted: Sat Mar 16, 2019 8:30 pm
since there is no delta v , your delta v would be 0 so your overall work would also be 0