### 4A 3

Posted:

**Sun Jan 26, 2020 9:23 pm**This question states that air in a bicycle pump is compressed by pushing in the

handle. The inner diameter of the pump is 3.0 cm and the pump is depressed 20. cm with a pressure of 2.00 atm. (a) How much work is done in the compression? (b) Is the work positive or negative with respect to the air in the pump? (c) What is the change in

internal energy of the system?

First of all, I do not know where to start and which equation to use. At first I thought it was w= - Pex * ΔV but I can't see how this would be used to find the work properly or if I'm using the right equation.

handle. The inner diameter of the pump is 3.0 cm and the pump is depressed 20. cm with a pressure of 2.00 atm. (a) How much work is done in the compression? (b) Is the work positive or negative with respect to the air in the pump? (c) What is the change in

internal energy of the system?

First of all, I do not know where to start and which equation to use. At first I thought it was w= - Pex * ΔV but I can't see how this would be used to find the work properly or if I'm using the right equation.