4A.3

$w=-P\Delta V$
and
$w=-\int_{V_{1}}^{V_{2}}PdV=-nRTln\frac{V_{2}}{V_{1}}$

Hannah_1G
Posts: 100
Joined: Wed Sep 18, 2019 12:22 am

4A.3

I cannot get the correct answer. I am using the area of a cylinder with .15 m as radius and .2 m as height times the height to get the volume times 2 atm as the pressure.

Alicia Lin 2F
Posts: 83
Joined: Wed Sep 18, 2019 12:17 am

Re: 4A.3

Pa x m^3 is equal to one Joule. You have to convert the atm to Pascals to make the units equivalent to a Joule. 1 atm=101325 Pascals.

Max Madrzyk Dis 4G
Posts: 102
Joined: Wed Sep 18, 2019 12:21 am

Re: 4A.3

work= -Pext x delta V
delta V= -pi x r^2 x d
use delta V and the pressure given in atm multiploied by the conversion to joules to find the amount of work done.