## second equation

$w=-P\Delta V$
and
$w=-\int_{V_{1}}^{V_{2}}PdV=-nRTln\frac{V_{2}}{V_{1}}$

connie 2C
Posts: 106
Joined: Thu Jul 11, 2019 12:17 am

### second equation

in the second equation, would we ever have to use the integral or would we just be using the equation -nRT(V2/V1)?

connie 2C
Posts: 106
Joined: Thu Jul 11, 2019 12:17 am

### Re: second equation

sorry the equation is -nRTln(V2/V1)*^

RichBollini4G
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Joined: Wed Sep 18, 2019 12:18 am

### Re: second equation

connie 2C wrote:in the second equation, would we ever have to use the integral or would we just be using the equation -nRT(V2/V1)?

I believe it depends on the question.

Vicki Liu 2L
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Joined: Sat Aug 24, 2019 12:15 am

### Re: second equation

I believe the integral was just involved in the process of deriving the equation.

Wendy 1E
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### Re: second equation

Unless asked to derive the equation, you would just use the -nRTln(v2/v1).

Posts: 102
Joined: Tue Oct 02, 2018 12:16 am

### Re: second equation

It is really used for when the pressure isn't constant do to find the work done, it is the integral of the subsequent volume changes. It is also used to derive the first formula.

nicole-2B
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Joined: Fri Aug 30, 2019 12:18 am

### Re: second equation

and this equation is used for reversible reactions only?

Sally Qiu 2E
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Joined: Fri Aug 30, 2019 12:18 am

### Re: second equation

if you solve the integral you would get ln( V2/V1).

Matthew Tsai 2H
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Joined: Wed Sep 18, 2019 12:20 am

### Re: second equation

In this case, the only time you would need to integrate would be if asked to derive the equation, in which case you would need to understand each step of the integral on a conceptual level. For actual calculations you can just use the formula.

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