## Units for Work

$w=-P\Delta V$
and
$w=-\int_{V_{1}}^{V_{2}}PdV=-nRTln\frac{V_{2}}{V_{1}}$

rachelle1K
Posts: 109
Joined: Sat Sep 07, 2019 12:16 am

### Units for Work

For $w=-P\Delta V$, are we expected to memorize that there are 101.325 J in 1L.atm ?

705302428
Posts: 50
Joined: Sat Aug 24, 2019 12:16 am

### Re: Units for Work

I think that would be given to us.

rachelle1K
Posts: 109
Joined: Sat Sep 07, 2019 12:16 am

### Re: Units for Work

I just looked it up and there is a chart in the textbook which explains that the pressure should be in Pa, and volume in m^3, so no conversions need to be done for this this equation.

Kate Swertfager
Posts: 50
Joined: Wed Sep 18, 2019 12:17 am

### Re: Units for Work

The SI units for pressure are Pascals and for V they are m^3. For work it is Joules so I think Pa times m^3 gives J.

Angus Wu_4G
Posts: 102
Joined: Fri Aug 02, 2019 12:15 am

### Re: Units for Work

If you check the equation sheet online in Dr.Lavelle's website, that specific value is given to you. (101.325J=1 LXatm)

You can also derive this conversion if you divide the 2 gas constants R, ((8.314J(K)^-1,(mol)^-1) / (0.08206 Latm (K)^-1(mol)^-1). You will find that the units cancel out to give you approximately 101.325J per 1 L atm

205405339
Posts: 77
Joined: Thu Jul 11, 2019 12:16 am

### Re: Units for Work

From what i remember, most professors usually provide conversions on the test in the form of a formula chart or at least include a needed conversion in the question