Integral for work

[Ellen Amico 2L]

Do we actually need to calculate the integral for the work equation when the system is at equilibrium or do we just calculate using -P∆V?

[Rory Simpson 2F]

When you have a reversible system, you would want to use the equation that you get from the integral because the changes in volume are infinitesimal. So, use w = -nRTln(V2/V1) for a reversible system, which you can derive from the integral.

[Jasmine Fendi 1D]

I don't think you need to directly calculate the work with the integral. Just memorize the equations that are derived from the integral and know when to use each one!

[Brian J Cheng 1I]

I would know why the equation exists. It exists in irreversible conditions (temperature constant, P and V changing at infinitesimally small intervals, so dw = -PdV. P becomes nRT/V, and if you take the integral of both sides you're left with w = -nRTln(V2/V1). It's just helpful to know in terms of linking concepts together.

[Kristina Rizo 2K]

I would know why the equation exists. It exists in irreversible conditions (temperature constant, P and V changing at infinitesimally small intervals, so dw = -PdV. P becomes nRT/V, and if you take the integral of both sides you're left with w = -nRTln(V2/V1). It's just helpful to know in terms of linking concepts together.

This was extremely helpful thank you!!