## Work without volume

$w=-P\Delta V$
and
$w=-\int_{V_{1}}^{V_{2}}PdV=-nRTln\frac{V_{2}}{V_{1}}$

Abigail Menchaca_1H
Posts: 104
Joined: Sat Sep 07, 2019 12:19 am

### Work without volume

Can we calculate work without knowing change in volume?

TimVintsDis4L
Posts: 104
Joined: Sat Aug 17, 2019 12:17 am

### Re: Work without volume

I don't know if this really helps, but if we are given the Internal Energy, q, or things that can be used to find q such as $\Delta S$ and t, then we can find q using $\Delta s = q/t$. Once you find the q, you can plug it into $\Delta U = q + w$ to get w.

J_CHEN 4I
Posts: 54
Joined: Tue Nov 14, 2017 3:01 am

### Re: Work without volume

The only types of work we need to know for thermodynamics are expansion work and non-expansion work, which involve volume change.

Sreyes_1C
Posts: 90
Joined: Fri Sep 28, 2018 12:19 am

### Re: Work without volume

since what we learned involves expansion of volume, we need the change in volume to see how much work is done

Chloe Alviz 1E
Posts: 102
Joined: Sat Aug 17, 2019 12:17 am

### Re: Work without volume

I think most of the problems that we do involve expansion work (so a change in volume is given), but since you can relate work with U = q + w, I assume you can find it through this equation given the internal energy and enthalpy.

Ryan Yee 1J
Posts: 101
Joined: Sat Aug 17, 2019 12:16 am

### Re: Work without volume

Since w=p(deltaV), not knowing the volume would mean you cant calculate work. But since U= q + w, given internal energy and enthalpy, you could calculate work.