Integral

$w=-P\Delta V$
and
$w=-\int_{V_{1}}^{V_{2}}PdV=-nRTln\frac{V_{2}}{V_{1}}$

Jorja De Jesus 2C
Posts: 121
Joined: Sat Jul 20, 2019 12:15 am

Integral

Why does the work of expansion at a constant pressure use volume for the integral?

Jiyoon_Hwang_2I
Posts: 101
Joined: Sat Sep 14, 2019 12:17 am

Re: Integral

Because if pressure is not changing the only thing changing is volume

Sydney Pell 2E
Posts: 100
Joined: Wed Sep 11, 2019 12:17 am

Re: Integral

Work of expansion at constant pressure has to incorporate volume because expansion is a change in volume. So, to calculate the work needed to change the volume,the integral should involve the volumes.