Equations
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Equations
I'm a bit confused but how do you know when to use -P(delta V) vs -(delta n)RT vs -nRTln(v2/v1) since they all account for work?
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Re: Equations
-P(delta V) and -(delta n)RT are both used for irreversible expansions. They are basically the same equation. I put the derivation below. The other equation, -nRTln(v2/v1), is used for reversible expansions. It can be derived from the the integral equation we covered in class.
Here is how to show that -P(delta V) = -(delta n)RT ...
PV = nRT
P(delta V) = (delta n)RT
delta V = (delta n)RT / P solve for delta V
Then ...
w = -P(delta V)
w = -P((delta n)RT / P) Plug the above solution for delta V in that was found from the PV = nRT equation
w = -(delta n)RT The pressure value (P) cancels out and we're left with the equation
Thus, -P(delta V) = -(delta n)RT
Here is how to show that -P(delta V) = -(delta n)RT ...
PV = nRT
P(delta V) = (delta n)RT
delta V = (delta n)RT / P solve for delta V
Then ...
w = -P(delta V)
w = -P((delta n)RT / P) Plug the above solution for delta V in that was found from the PV = nRT equation
w = -(delta n)RT The pressure value (P) cancels out and we're left with the equation
Thus, -P(delta V) = -(delta n)RT
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Re: Equations
In addition, I understand that work is the integral from v2 to v1 (-p(delta v)), but how does it also equal -nRTln(v2/v1)?
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Re: Equations
You would use -P(delta V) when there is a constant external pressure. You use -nRTln(V2/V1) when the reaction is an isothermal, reversible one.
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Re: Equations
it depends on whether pressure is constant or not. You can use -P(delta)V when external pressure is constant and the other when it isn't.
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