## solving for work

$w=-P\Delta V$
and
$w=-\int_{V_{1}}^{V_{2}}PdV=-nRTln\frac{V_{2}}{V_{1}}$

Ashley Chen
Posts: 21
Joined: Fri Sep 25, 2015 3:00 am

### solving for work

Whenever we are solving for work, we use the multiply 101.35 J/ (atm x L) after using -P x change in volume right?

Matthew Gutierrez 2D
Posts: 19
Joined: Fri Sep 25, 2015 3:00 am

### Re: solving for work

Yes, because you want the units to cancel out so that you are left with joules.

Chem_Mod
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### Re: solving for work

Just making sure that P is in atm and deltaV is in L.