Txtbk Question 4A.9


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Mia_Renna_1L
Posts: 91
Joined: Mon Jan 09, 2023 8:39 am

Txtbk Question 4A.9

Postby Mia_Renna_1L » Sun Feb 05, 2023 6:49 pm

Why is the heat lost by metal equal to the negative heat gained by water?

705968973
Posts: 39
Joined: Mon Jan 09, 2023 9:51 am

Re: Txtbk Question 4A.9

Postby 705968973 » Sun Feb 05, 2023 7:47 pm

This is a classic example of heat lost and gained by system vs. surrounding. In the case of a metal being surrounded by water in a calorimeter, the metal represents the system whereas the water represents the surrounding. The heat lost by the system (metal) is q and the heat gained by the water (the surrounding) is -q. -smdeltat = smdeltat is a common equation used for these kinds of questions, where smdeltat is the heat lost by the system and -smdeltat is the heat gained by the surrounding.

Richard Chiu 1I
Posts: 47
Joined: Mon Jan 09, 2023 8:29 am

Re: Txtbk Question 4A.9

Postby Richard Chiu 1I » Sun Feb 05, 2023 9:41 pm

The above response does a great job help explain the question! I'd also want to add that this is an application of the First Law of Thermodynamics, where the energy is completely transferred from the metal (system) to the water (surroundings).


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