Txtbk Question 4A.13

[Mia_Renna_1L]

Hi, can someone please explain how to start this problem and possibly walk through the steps? Thanks!

[Joshua Chandran 2D]

First, the information about the calibration of the calorimeter will allow us to find the heat capacity of the calorimeter. We find this by doing to find the heat capacity: (3.50 kJ)/(7.32 K) = 0.478 kJ/K ( in Celsius is the same as in Kelvin).

With this, now we can apply the equation, to find the heat given off by the neutralization reaction. By plugging in the correct numbers, you should get that the q value for the reaction is -1.19 kJ. This value will also be our change in internal energy as there was no work of expansion done by the reaction, so .

If you want a more thorough explanation, example 4A.4 in the textbook describes a very similar problem in detail.