Limiting Reagents
Moderators: Chem_Mod, Chem_Admin
-
- Posts: 51
- Joined: Fri Sep 24, 2021 5:51 am
Limiting Reagents
Photosynthesis is essential for life: plants convert CO2 and H2O into glucose (C6H12O6), a primary source of energy, and oxygen, which is needed for respiration. If 10.00 grams of CO2 react with 20.00 grams of water, what is the limiting reagent? How many grams of glucose are produced? (Glucose has a molar mass of 180.156 g/mol)
-
- Posts: 102
- Joined: Fri Sep 24, 2021 6:06 am
- Been upvoted: 1 time
Re: Limiting Reagents
There will be 6.823 g of C6H12O6 produced. Divide 10.00 g CO2 by its molar mass (44.01 g) to get the amount of moles. Divide 20.00 g H2O by its molar mass (18.016 g) to get the amount of moles. Carbon dioxide and water have a 1:1 molar ratio, so since there is more of H2O, CO2 is the limiting reagent. 0.2272 mol CO2 x (1 mol Glucose)/(6 mol CO2) x (180.156 g)/(1 mol Glucose) = 6.823 g.
-
- Posts: 80
- Joined: Fri Sep 24, 2021 7:09 am
Re: Limiting Reagents
6.823 g of C6H12O6 will be produced, because CO2 is the limiting reagent. Just follow the steps we learned in the modules and in class, and you should, be able to see how to get this answers.
Return to “Limiting Reactant Calculations”
Who is online
Users browsing this forum: No registered users and 8 guests