Review Question M9  [ENDORSED]

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AllisonKimbell
Posts: 7
Joined: Tue Jun 21, 2016 3:00 am

Review Question M9

Postby AllisonKimbell » Sun Jun 26, 2016 12:52 am

Hello all, having an issue currently with this problem.

Copper (II) nitrate reacts with sodium hydroxide to produce precipate of light blue copper (II) hydroxide.
A) write net ionic equation for reaction

The issue is that the solutions manual puts this as:
Cu^2+ (aq) + 2OH^- (aq). --> Cu(OH)sub2 (s)

Where did the nitrate and sodium go???

But then for (b) it includes the NaOH and nitrate...confused please help
Thanks~

Chem_Mod
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Joined: Thu Aug 04, 2011 1:53 pm
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Re: Review Question M9  [ENDORSED]

Postby Chem_Mod » Sun Jun 26, 2016 1:43 pm

for ionic equation, if some ion didn't get involve in the reaction (i.e not forming precipitates or gas) you don't have to show them. This is the same as writing Na+ on both sides of the equation and then cancel them.


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