Exercise M.11 - Part (c)

Moderators: Chem_Mod, Chem_Admin

Amy Wu 1D
Posts: 24
Joined: Fri Jun 23, 2017 11:39 am

Exercise M.11 - Part (c)

Postby Amy Wu 1D » Wed Jul 05, 2017 6:37 pm

A reaction vessel contains 5.77 g of white phosphorus and 5.77 g of oxygen. The first reaction to take place is the formation of phosphorus(III) oxide,
P4O6: P4(s) + 3 O2(g) --> P4O6(s). If enough oxygen is present, the oxygen can react further with this oxide to produce phosphorus(V) oxide, P4O10: P4O6(s) + 2O2(g) --> P4O10(s). (a) What is the limiting reactant for the formation of P4O10? (b) What mass of P4O10 is produced? (c) How many grams of the excess reactant remain in the reaction vessel?

For (c), which reaction's excess reactant is being referred to? Is it the excess reactant in the first reaction (P4O6) or the second reaction (P4O10)?

alexis castro 1B
Posts: 30
Joined: Wed Nov 16, 2016 3:02 am

Re: Exercise M.11 - Part (c)

Postby alexis castro 1B » Wed Jul 05, 2017 6:46 pm

It is referring to the excess amount of reactant in the second reaction.

Return to “Limiting Reactant Calculations”

Who is online

Users browsing this forum: No registered users and 1 guest