M9

[Sarah Brecher 1I]

The question is:
Copper nitrate reacts with sodium hydroxide to produce a precipitate of light blue copper hydroxide.

In order to do this problem, I understand I need to find the balanced equation. When looking up the formula for those compounds, I get Cu(NO3)2 for copper nitrate, NaOH for sodium hydroxide, and Cu(OH)2 for copper hydroxide. This equation isn't balanced and doesn't use the N or Na from the left hand side and I can't seem to figure out what the other products are. What are the other products so that I can figure out the rest of the problem?

Also, part a asks for the net ionic equation for the reaction. What is that? Thanks!

[Gisselle Sainz 2F]

If I'm not mistaken, I believe the chemical equation should be
Cu(NO3)2 + 2 NaOH ---> Cu(OH)2 + 2 NaNO3

[Caitlyn Ponce 1L]

Net ionic equations do not include spectator ions (these ions are present in the reaction, but do not participate in it). You can find spectator ions by looking for ions that are in the same state and number on both sides of the equation, basically they remain unchanged throughout the reaction.