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When determining the amounts in limiting reactants of a molecule, do we multiply 1 mole of that atom by the stoichiometric coefficient in the balanced equation? for example in CaC2 + 2 H2O -> Ca(OH)2 + C2H2 do we multiply the moles of CaC2 by 2 because of the 2 moles of hydrogen?
I'm not sure I understand your question, but to determine limiting reactant you can convert the grams of both reactants to moles of the same product, the reactant that results in the lesser moles of product will determine how much product is made and is therefore your limiting reactant.
If you want to find the limiting reactant of this question, you would first need to calculate the number of moles present of each reactant (by using the molar mass and given mass). Then use the ratio of 1 mole of CaC2: 2 moles of H2O to deduce which of the reactants is actually present in excess.
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