Limiting Reactants

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Jonathan Marcial Dis 1K
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Joined: Fri Apr 06, 2018 11:03 am

Limiting Reactants

Postby Jonathan Marcial Dis 1K » Sun Apr 15, 2018 10:27 pm

When determining the amounts in limiting reactants of a molecule, do we multiply 1 mole of that atom by the stoichiometric coefficient in the balanced equation? for example in CaC2 + 2 H2O -> Ca(OH)2 + C2H2 do we multiply the moles of CaC2 by 2 because of the 2 moles of hydrogen?

Jose Munoz 1D
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Re: Limiting Reactants

Postby Jose Munoz 1D » Sun Apr 15, 2018 10:29 pm

I believe that you multiply by the ratio, so your assumption is right.

Chem_Mod
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Re: Limiting Reactants

Postby Chem_Mod » Sun Apr 15, 2018 10:58 pm

I am not quite understanding your question, but to determine the limiting reactant you do need to take account of the stoichiometric relation of a balanced equation of interest.

204917020
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Joined: Fri Apr 06, 2018 11:05 am

Re: Limiting Reactants

Postby 204917020 » Sun Apr 15, 2018 11:14 pm

I'm not sure I understand your question, but to determine limiting reactant you can convert the grams of both reactants to moles of the same product, the reactant that results in the lesser moles of product will determine how much product is made and is therefore your limiting reactant.

105012653 1F
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Re: Limiting Reactants

Postby 105012653 1F » Sun Apr 15, 2018 11:49 pm

Also confused on this

Salena Chowdri 1I
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Re: Limiting Reactants

Postby Salena Chowdri 1I » Wed Apr 18, 2018 9:06 pm

If you want to find the limiting reactant of this question, you would first need to calculate the number of moles present of each reactant (by using the molar mass and given mass). Then use the ratio of 1 mole of CaC2: 2 moles of H2O to deduce which of the reactants is actually present in excess.


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