Fundamental M.9  [ENDORSED]

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Leslie Cheng 4B
Posts: 35
Joined: Fri Sep 28, 2018 12:29 am

Fundamental M.9

Postby Leslie Cheng 4B » Wed Oct 03, 2018 10:21 pm

Hi, this problem states that copper (II) nitrate reacts with sodium hydroxide to produce a precipitate of light blue copper (II) hydroxide. It asks you to write the net ionic equation for the reaction. What does net ionic equation mean?

Ramsha Dis1B
Posts: 32
Joined: Fri Sep 28, 2018 12:19 am

Re: Fundamental M.9

Postby Ramsha Dis1B » Wed Oct 03, 2018 10:40 pm

I believe that first you can write the soluble ionic compounds as dissociated ions to get the complete ionic equation but you still have leave out the spectator ions (the ones that stay the same in the reactant and product side) from the equation since they do not change.

Ania Chavez Dis 4D
Posts: 14
Joined: Fri Sep 28, 2018 12:27 am

Re: Fundamental M.9  [ENDORSED]

Postby Ania Chavez Dis 4D » Wed Oct 03, 2018 11:12 pm

A net ionic equation is a chemical equation that only shows elements, compounds, or ions that are directly involved in the chemical reaction.
So when you write out the ionic equation for NaOH + Cu(NO3)2 --> Cu(OH)2 + NaNO3 :
Cu2+ + 2NO3- + 2Na+ + 2OH- ---> Cu(OH)2 + 2Na+ + 2NO3-

Since 2Na+ and 2NO3- remain unchanged on both sides, they are not involved in the chemical reaction.
The final net ionic equation is:
Cu2+ + 2OH- --> Cu(OH)2

sorry if i wrote too much or explained wrong.

ThomascnguyenDis1J
Posts: 30
Joined: Fri Sep 28, 2018 12:16 am

Re: Fundamental M.9

Postby ThomascnguyenDis1J » Thu Oct 04, 2018 8:10 pm

Thank you Ania for the explanation. It really helped a lot. So would you say that if they ask you for any net equation and there is a reactant and product that does not change, they would just cancel each other out?


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