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Question 34 on Module 3

Posted: Thu Oct 04, 2018 2:12 pm
by 705170809
For some reason, I keep getting .014 grams of HCl at the end instead of any of the options on the quiz. Please help :)

Re: Question 34 on Module 3  [ENDORSED]

Posted: Thu Oct 04, 2018 2:18 pm
by 305113590
1. Balance the equation. PCl3 + 3H20 --> 3HCl + H3PO3
2. Convert PCl3 to to moles. (23.6g)/(137.32g)= .172 mol of PCL3
3. Use stoichiometry .172 mol(3 mol HCL)= .516 mol HCL
4. Convert .515 mol HCl to grams. .516mol(36.46g)= 18.8g HCl