Finding Limiting Reactants

Moderators: Chem_Mod, Chem_Admin

katherinemurk 2B
Posts: 68
Joined: Wed Nov 15, 2017 3:02 am

Finding Limiting Reactants

Postby katherinemurk 2B » Sat Oct 06, 2018 10:32 am

Is the limiting reactant always going to be the one with the least moles? or do you have to take into account the molar ratio? and if you do take into account the molar ratio how would you work that into finding the limiting reactant??

Jaifreen_Bhangu_3K
Posts: 34
Joined: Fri Sep 28, 2018 12:26 am

Re: Finding Limiting Reactants

Postby Jaifreen_Bhangu_3K » Sat Oct 06, 2018 12:22 pm

I believe it is the one with the least moles. At least, that's how a limiting reactant was defined in class.

Sydney Aurelio_Dis4B
Posts: 30
Joined: Fri Sep 28, 2018 12:28 am

Re: Finding Limiting Reactants

Postby Sydney Aurelio_Dis4B » Sat Oct 06, 2018 12:40 pm

The limiting reactant is the reactant that's actual amount (in moles) is less than the theoretical amount of that reactant needed (in moles). You would pick one reactant and then use stoichiometry to find the theoretical amount of the other reactant. If the actual amount in moles of one reactant is more than its theoretical value then the other reactant is automatically the limiting reactant.
Last edited by Sydney Aurelio_Dis4B on Sat Oct 06, 2018 12:48 pm, edited 1 time in total.

EllerySchlingmann1E
Posts: 76
Joined: Fri Sep 28, 2018 12:24 am

Re: Finding Limiting Reactants

Postby EllerySchlingmann1E » Sat Oct 06, 2018 12:46 pm

You do need to take molar ratio into consideration. While amount of moles definitely matters, if the molar amounts are similar for the reactants, comparing their molar ratios with the product you are trying to find will give you a definite limiting reactant. In order to incorporate the molar ratio into your calculation, just continue the calculation after finding the moles of each reactant by multiplying it by the molar ratio of reactant to chosen product. Hope that helps!


Return to “Limiting Reactant Calculations”

Who is online

Users browsing this forum: No registered users and 1 guest