Calculating the amount of moles

[tessadalke]

How many moles of CO2(g) are produced when 1 kg of CaCO3(s) is used to neutralize an acid spill? The equation for the reaction at 1 atm and 25 degrees C is:

CaCO3(s) + H2SO4(aq) ---> CaSO4(s) + CO2(g) + H2O(l)

For this question, I am just confused about where to start.

[Beatrice Petelo 1F]

Hello!

I would convert the 1 kg of CaCO3 into grams and then moles
(1kg CaCO3) x (1000g/1kg) x (1mol/100.0869g -- molar mass of CaCO3) = 9.99131 which is about 10 mol CaCO3

Based on the molar ratio in the balanced equation, 1 mole of CaCO3 = 1 mole of CO2

Therefore, 10 moles of CO2 will be produced from 1 kg of CaCO3.

Hope this helps!

[MinaChoi_3H]

To start, convert the 1kg of CaCO3(s) to grams then moles (by dividing its weight by its molar mass). This question is essentially a "If you have this much of this reactant, how much of this product will be produced?" So basically convert the given amount of the reactant to moles by dividing it by its molar mass, then use the molar ratio between the reactant and product to see how how much moles of the product will be produced.

[Pritish Patil 1K]

In the beginning you should convert the 1kg of CaCO3(s) to grams (1kg=1000g). Secondly, divide by the molar mass for CaCO3 in order to get the number of moles. Because the chemical equation is already balanced, simply look at the mole ratio between CaCO3 and see how many moles of the product will be produced. In this case, because it is a one-to-one mole ratio, 10 moles of the CO2 will be produced from 10 moles of the CaCO3.