M.9

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KNguyen_1I
Posts: 101
Joined: Sat Aug 17, 2019 12:16 am

M.9

Postby KNguyen_1I » Wed Oct 02, 2019 3:58 pm

M.9 Copper(II) nitrate reacts with sodium hydroxide to produce
a precipitate of light blue copper(II) hydroxide. (a) Write the
net ionic equation for the reaction. (b) Calculate the maximum
mass of copper(II) hydroxide that can be formed when 2.00 g of
sodium hydroxide is added to 80.0 mL of 0.500 m Cu(NO3)2(aq).

How do you find the net ionic equation?

sarahsalama2E
Posts: 164
Joined: Fri Aug 30, 2019 12:16 am

Re: M.9

Postby sarahsalama2E » Wed Oct 02, 2019 4:07 pm

So the net ionic equation is essentially the chemical reaction with only the things that are participating in the reaction. Things that are not found on BOTH the reactants and products side of the reaction are called spectators and are NOT involved in the net ionic equation. Essentially, when making a net ionic equation for a chemical reaction, your job is to identify what is present on BOTH sides of the reaction.

In this case,
the net ionic equation would be
Cu 2+ + 2OH- ---> Cu(OH)2

Cassandra_1K
Posts: 49
Joined: Wed Sep 18, 2019 12:16 am

Re: M.9

Postby Cassandra_1K » Wed Oct 02, 2019 4:13 pm

I'm not completely sure how to find the ionic equation, but I believe you start off by balancing equations and then separating each element with its individual ionic charge and the number of each ion.

AVerma_F19
Posts: 59
Joined: Thu Jul 25, 2019 12:15 am
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Re: M.9

Postby AVerma_F19 » Wed Oct 02, 2019 4:23 pm

The net ionic reaction essentially means that you only include atoms/molecules that do NOT remain in an aqueous state after the reaction has completed.

Jade Hinds 2B
Posts: 75
Joined: Tue Sep 10, 2019 12:16 am

Re: M.9

Postby Jade Hinds 2B » Wed Oct 02, 2019 4:27 pm

Yes, to find the net ionic equation, start by balancing the equation first...
-i don't believe we've gone over this in lecture yet, but the second step is to break all of the strong electrolytes into the ions they form
-last step= any that are aqueous on both sides of the chemical equation get cancelled out (= spectator ions), which are not re-written as part of the reaction

*again, we will probably learn these steps in depth in the future :)

Sanjana K - 2F
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Re: M.9

Postby Sanjana K - 2F » Thu Oct 03, 2019 2:22 am

Your net ionic equation does not include spectator ions (because they're essentially the elements that don't react with water; they just sit there). Spectator ions cancel out on each side of the reaction. I do think it would be a good idea to commit some of these spectator ions to memory because it'll help when we study aqueous equilibria.

Here are some common spectators: (You'll notice alkalis)
Li+
Na+
K+
Ba(2+)
Cl-
Br-
I-
NO3-
SO4(2-)


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