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Mass of AgCl produced?

Posted: Fri Oct 04, 2019 8:39 am
by Cole Reynolds 4F
According to the following equation, 0.750 g of C6H9Cl3 is mixed with 1.000 kg of AgNO3 in a flask of water. A white solid, AgCl, completely precipitates out. What is the mass of AgCl produced?

C6H9Cl3 + 3AgNO3 ---> AgCl + C6H9(NO3)3.

Molar Mass: C6H9Cl3 (187.50 g/mol), 3AgNO3 (169.88 g/mol), AgCl (143.32 g/mol)

I found that the limiting reactant is C6H9Cl3 and that the moles of this molecule are .004 moles but I am unsure about what to do after this.

Re: Mass of AgCl produced?

Posted: Fri Oct 04, 2019 11:12 am
by Chem_Mod
After you've found the limiting reactant and you've determined the number of moles of AgCl that would be produced by the reaction, you would multiply the # of moles of AgCl you calculated by the molar mass of AgCl and that should give you the mass of AgCl produced.

Re: Mass of AgCl produced?

Posted: Fri Oct 04, 2019 9:56 pm
by Eesha Chattopadhyay 2K
Use the balanced equation to determine how many moles of product can be made with that many moles AgCl. Then multiply that number by the molar mass that you've given to determine how many grams of that product has been created