2A + 1B ---> 3C

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Cole Reynolds 4F
Posts: 5
Joined: Thu Jul 11, 2019 12:17 am

2A + 1B ---> 3C

Postby Cole Reynolds 4F » Fri Oct 04, 2019 9:07 am

2A + 1B ---> 3C

If one mole of A is mixed with one mole of B which is the limiting reactant?
How much of B would be used?
What is the maximum amount of product that can be produced?

I'm having trouble understanding how A would end up being the limiting reactant if there are fewer moles of B. Could someone walk me through this one? Thanks!

Jonathan Gong 2H
Posts: 105
Joined: Sat Jul 20, 2019 12:16 am

Re: 2A + 1B ---> 3C

Postby Jonathan Gong 2H » Fri Oct 04, 2019 9:23 am

A is the limiting reactant because it takes twice as many moles of A, when compared to B, to produce the same amount of C due to their coefficients. If 1 mol of A is used, only 0.5 mol of B is used, again, because of their coefficient ratio of 2 mol A: 1 mol B. Essentially, you should always look at the coefficients of reactants because depending on which reactant has a higher one, it suggests it takes more of that specific reactant to produce whatever is on the product side of a reaction. But, of course, always consider how many moles of reactant there are and use dimensional analysis to solve for moles of product produced if each reactant is completely used.

Charysa Santos 4G
Posts: 107
Joined: Wed Sep 18, 2019 12:21 am

Re: 2A + 1B ---> 3C

Postby Charysa Santos 4G » Fri Oct 04, 2019 9:44 am

If 1 mole of A reacted with 1 mole of B, but the reaction requires *2* moles of A to react with every 1 mole of B, then there is a limited amount of A present and that limits the amount of product that can be formed. The reaction would still proceed, with 1 mole of A reacting with 0.5 mole of B (the ratio is still 2:1 for A:B) but there would only be 1.5 moles of product (C) formed, which is because there isn't enough of A to form the 3 moles of C.

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