Fundamentals M Homework Problem M.11

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Charysa Santos 4G
Posts: 107
Joined: Wed Sep 18, 2019 12:21 am

Fundamentals M Homework Problem M.11

Postby Charysa Santos 4G » Thu Oct 10, 2019 10:02 pm

Is there another way to find the limiting reactant aside from converting the grams of P into the grams of O2? I don't understand how converting the grams into O2 would tell you that it is the limiting reactant. Can anyone clarify?

Eugene Chung 3F
Posts: 142
Joined: Wed Nov 15, 2017 3:03 am

Re: Fundamentals M Homework Problem M.11

Postby Eugene Chung 3F » Thu Oct 10, 2019 10:17 pm

you can use other ways to find out what the limiting reactant is. I think we use o2 to do so since to solve the next part of the question, you have to calculate how much excess o2 you get.

Charysa Santos 4G
Posts: 107
Joined: Wed Sep 18, 2019 12:21 am

Re: Fundamentals M Homework Problem M.11

Postby Charysa Santos 4G » Fri Oct 11, 2019 10:07 am

Oh okay, fair enough. I was just confused because the solution shows that there is an excess of oxygen (for example, for the first reaction it shows: excess O2 = 5.77g - 4.47g = 1.30g O2). But now I think I understand why O2 is still the limiting reactant.

Brittney Hun 2C
Posts: 104
Joined: Wed Sep 11, 2019 12:15 am

Re: Fundamentals M Homework Problem M.11

Postby Brittney Hun 2C » Sun Oct 13, 2019 9:38 am

There are multiple ways to finding the limiting reagent. You could also start with the grams of water and see how much water is needed in moles or grams to complete the reaction (since it is the product) and then find how much o2 we already have. You can compare those values and see how much is excess or limited depending on the situation.


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