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Is there another way to find the limiting reactant aside from converting the grams of P into the grams of O2? I don't understand how converting the grams into O2 would tell you that it is the limiting reactant. Can anyone clarify?
Oh okay, fair enough. I was just confused because the solution shows that there is an excess of oxygen (for example, for the first reaction it shows: excess O2 = 5.77g - 4.47g = 1.30g O2). But now I think I understand why O2 is still the limiting reactant.
There are multiple ways to finding the limiting reagent. You could also start with the grams of water and see how much water is needed in moles or grams to complete the reaction (since it is the product) and then find how much o2 we already have. You can compare those values and see how much is excess or limited depending on the situation.
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