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Sapling #10 Walkthrough
Posted: Tue Oct 06, 2020 11:48 am
by Julianna Shimabukuro 1D
Does someone mind walking me through how to do #10 on Sapling? I know that you're supposed to find the mass of the reactant by multiplying the density and the volume of the reactant, but I'm confused on what to do next.
Re: Sapling #10 Walkthrough
Posted: Tue Oct 06, 2020 12:04 pm
by Astha Sahoo 3I
Divide the grams of 2-butanone by its molar mass to calculate the number of moles.Multiply the number of moles of 2-butanone by the molar mass of the product, since there are no molar coefficients in this problem. This will give you the theoretical yield (should be 0.78g). Then, divide the actual mass by the theoretical yield and multiply by 100 to get the percent yield (0.59/0.78 * 100 = 75%).
Re: Sapling #10 Walkthrough
Posted: Tue Oct 06, 2020 12:05 pm
by Melody Haratian 2J
After you find the mass of the 2-butanone, find the number of moles of the 2-butanone by dividing the mass by its molar mass. The molar mass of 2-butanone is 72.1 g/mol.
The number of moles of 3-methyl-3-hexanone is equal to the number of moles of the 2-butanone. Using the molar mass of the 3-methyl-3-hexanone (116.2 g/mol) convert the moles of the 3-methyl-3-hexanone into grams of it. Once you find the value of the compound in grams, you have the theoretical yield/ max amount of product possible. You can find the percent yield by dividing the actual yield of product (.29g) by the theoretical yield that you find then multiply it by 100%.
I hope this helps!
Re: Sapling #10 Walkthrough
Posted: Tue Oct 06, 2020 10:12 pm
by lwon Dis2I
How do you find the molar mass of 2‑butanone?
Re: Sapling #10 Walkthrough
Posted: Tue Oct 06, 2020 10:18 pm
by lwon Dis2I
Also, what does the "d" below each of the reactants and products mean?
Re: Sapling #10 Walkthrough
Posted: Tue Oct 06, 2020 10:58 pm
by Hailey Qasawadish 2J
lwong Dis1L wrote:Also, what does the "d" below each of the reactants and products mean?
The D below each of the reactants and products represents density in grams/mL. This allows you to have a conversion factor in order to get to moles. Hope this helps. :)
Re: Sapling #10 Walkthrough
Posted: Tue Oct 06, 2020 11:01 pm
by Hailey Qasawadish 2J
lwong Dis1L wrote:How do you find the molar mass of 2‑butanone?
You find the molar mass of 2-butanone with the chemical formula. You can find out from the picture that there are 4 carbons, 8 hydrogens, and 1 oxygen by looking at the structure. (I wasn't sure at first how to count the carbons and hydrogens, so I looked up the chemical formula) Then, add the molar masses for each element (times the number of moles of each) to get the total molar mass of the compound. So you would do 4(12.01) + 8(1.008) + 1(16).